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The state of hybridization of the central atom is not the same as in the others :A B in BF3 B O in H3O+ C N in NH3 D P in PCl3

Question

The state of hybridization of the central atom is not the same as in the others:

  • A B in BF3
  • B O in H3O+
  • C N in NH3
  • D P in PCl3
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Solution

The hybridization of the central atom in each molecule is as follows:

A. B in BF3: The boron atom is surrounded by three regions of electron density (three single bonds to fluorine atoms), which means it is sp2 hybridized.

B. O in H3O+: The oxygen atom is surrounded by four regions of electron density (one lone pair and three single bonds to hydrogen atoms), which means it is sp3 hybridized.

C. N in NH3: The nitrogen atom is surrounded by four regions of electron density (one lone pair and three single bonds to hydrogen atoms), which means it is sp3 hybridized.

D. P in PCl3: The phosphorus atom is surrounded by three regions of electron density (three single bonds to chlorine atoms), which means it is sp2 hybridized.

So, the molecule that has a different hybridization state for the central atom is B. O in H3O+. This molecule is sp3 hybridized, while the others are sp2 hybridized.

This problem has been solved

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