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Factor the polynomial completely. Must show work/steps on your work page3⁢𝑥3+19⁢𝑥2−40⁢𝑥 =

Question

Factor the polynomial completely.

Must show work/steps on your work page
3x3+19x240x 3x^3 + 19x^2 - 40x

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Solution

Sure, let's factor the polynomial 3x3+19x240x3x^3 + 19x^2 - 40x step by step.

Step 1: Factor out the Greatest Common Factor (GCF)

First, we look for the greatest common factor (GCF) of all the terms in the polynomial. In this case, each term has an xx in common.

3x3+19x240x=x(3x2+19x40)3x^3 + 19x^2 - 40x = x(3x^2 + 19x - 40)

Step 2: Factor the Quadratic Expression

Next, we need to factor the quadratic expression 3x2+19x403x^2 + 19x - 40. We will use the method of factoring by grouping.

Step 2.1: Find two numbers that multiply to aca \cdot c and add to bb

For the quadratic ax2+bx+cax^2 + bx + c, we need to find two numbers that multiply to aca \cdot c and add to bb.

Here, a=3a = 3, b=19b = 19, and c=40c = -40.

ac=3(40)=120a \cdot c = 3 \cdot (-40) = -120 We need two numbers that multiply to 120-120 and add to 1919. These numbers are 2424 and 5-5.

Step 2.2: Rewrite the middle term using these two numbers

Rewrite 19x19x as 24x5x24x - 5x:

3x2+19x40=3x2+24x5x403x^2 + 19x - 40 = 3x^2 + 24x - 5x - 40

Step 2.3: Factor by grouping

Group the terms in pairs and factor out the common factors from each pair:

3x2+24x5x40=3x(x+8)5(x+8)3x^2 + 24x - 5x - 40 = 3x(x + 8) - 5(x + 8)

Step 2.4: Factor out the common binomial factor

Now, factor out the common binomial factor (x+8)(x + 8):

3x(x+8)5(x+8)=(3x5)(x+8)3x(x + 8) - 5(x + 8) = (3x - 5)(x + 8)

Step 3: Combine the factors

Now, we combine the factors we have found:

x(3x2+19x40)=x(3x5)(x+8)x(3x^2 + 19x - 40) = x(3x - 5)(x + 8)

Final Answer

The completely factored form of the polynomial 3x3+19x240x3x^3 + 19x^2 - 40x is:

3x3+19x240x=x(3x5)(x+8)3x^3 + 19x^2 - 40x = x(3x - 5)(x + 8)

This problem has been solved

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