How many three-digit numbers are greater than 100 and increase by 198 when the three digits are arranged in the reverse order?
Question
Solution 1
To solve this problem, we need to find the three-digit numbers that increase by 198 when their digits are reversed.
Step 1: Let's denote the three-digit number as ABC, where A, B, and C are its digits. When reversed, it becomes CBA.
Step 2: According to the problem, CBA = ABC + 198.
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