The difference between a three digit number and the number formed by reversing its digits is 198. Find the difference of its first and last digits.a.4b.2c.1d.3
Question
Solution
Let's denote the three-digit number as ABC, where A, B, and C are its digits. When reversed, it becomes CBA.
According to the problem, we have the equation:
ABC - CBA = 198
This can be rewritten as:
100A + 10B + C - (100C + 10B + A) = 198
Simplifying this equation, we get:
99A - 99C = 198
Dividing the entire equation by 99, we get:
A - C = 2
So, the difference between the first and last digits of the number is 2.
Therefore, the correct answer is (b) 2.
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