What causes silver bromide (AgBr) to exhibit both Schottky and Frenkel defects?
Question
What causes silver bromide (AgBr) to exhibit both Schottky and Frenkel defects?
Solution
Silver bromide (AgBr) is a compound that can exhibit both Schottky and Frenkel defects due to its unique crystal structure and the nature of its constituent ions.
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Schottky Defect: This type of defect occurs when equal numbers of cations and anions are missing from the crystal lattice, resulting in a decrease in the density of the substance. In the case of AgBr, both silver (Ag+) and bromide (Br-) ions can occasionally vacate their lattice sites, creating vacancies. This happens to maintain electrical neutrality. The occurrence of Schottky defect in AgBr is due to the comparable sizes of Ag+ and Br- ions.
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Frenkel Defect: This defect is observed when a smaller ion (usually a cation) leaves its normal site in the lattice and moves to an interstitial site. This results in a vacancy defect at the original site and an interstitial defect at the new location. In AgBr, the silver ion (Ag+) is small enough to move from its lattice site to an interstitial site, creating a Frenkel defect. This does not change the density of the crystal but increases the dielectric constant and conductivity.
So, the ability of AgBr to exhibit both Schottky and Frenkel defects is due to the nature of its ions and their ability to create vacancies (Schottky) or move to interstitial sites (Frenkel).
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