# The sum of the squares of two consecutive natural numbers is 41. Find the numbers.

## Question

## Solution 1

Sure, let's solve this step by step.

Step 1: Let's denote the two consecutive natural numbers as n and n+1.

Step 2: According to the problem, the sum of the squares of these two numbers is 41. So, we can write the equation as:

n^2 + (n+1)^2 = 41

Step 3: Expand the equation:

n^2 + n^2 + 2n + 1 = Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.

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```

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