A ball rolls off a 5 meter high deck at 5 m/s. How fast will the ball be moving when it hits the ground?≈ 11 m/s≈ 8 m/s ≈ 9 m/s≈ 15 m/s

To solve this problem, we can use the equation of motion that relates final velocity, initial velocity, acceleration and displacement. The equation is:

v² = u² + 2as

where: v is the final velocity (which we are trying to find), u is the initial velocity (5 m/s in this case), a is the acceleration (which is acceleration due to gravity, approximately 9.8 m/s²), and s is the displacement (5 m in this case).

Substituting the given values into the equation, we get:

v² = (5 m/s)² + 2*(9.8 m/s²)*(5 m)

Solving this, we get:

v² = 25 m²/s² + 98 m²/s²

v² = 123 m²/s²

Taking the square root of both sides to solve for v, we get:

v = √123 m/s

v ≈ 11 m/s

So, the ball will be moving at approximately 11 m/s when it hits the ground.