A ball is thrown up at a speed of 4 m/s. Find maximum height reached by the ballis ____ (take 210 /g m s )A) 8 mts B) -8 mts C) 0.80 mts D) -0.8 mts
Question
A ball is thrown up at a speed of 4 m/s. Find maximum height reached by the ball is ____ (take 210 /g m s )
A) 8 mts
B) -8 mts
C) 0.80 mts
D) -0.8 mts
Solution
To solve this problem, we can use the formula for the maximum height reached by a projectile, which is given by:
h = (u^2) / (2g)
where:
- h is the maximum height,
- u is the initial velocity (speed of the ball when it was thrown), and
- g is the acceleration due to gravity.
Given in the problem, u = 4 m/s and g = 10 m/s^2.
Substituting these values into the formula, we get:
h = (4 m/s)^2 / (2 * 10 m/s^2) = 16 m^2/s^2 / 20 m/s^2 = 0.8 m
So, the maximum height reached by the ball is 0.8 meters. Therefore, the correct answer is C) 0.80 mts.
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