To find the gradient and the y-intercept of the line, we first need to rearrange the equation into the slope-intercept form, which is y = mx + b, where m is the gradient (slope) and b is the y-intercept.

The given equation is 3y + 2x = 12.

Step 1: Subtract 2x from both sides to isolate y on one side of the equation:
3y = -2x + 12

Step 2: Divide every term by 3 to solve for y:
y = -2/3x + 4

So, the gradient (slope) of the line is -2/3 and the y-intercept is 4.

Question

To find the gradient and the y-intercept of the line, we first need to rearrange the equation into the slope-intercept form, which is y = mx + b, where m is the gradient (slope) and b is the y-intercept.

The given equation is 3y + 2x = 12.

Step 1: Subtract 2x from both sides to isolate y on one side of the equation:
3y = -2x + 12

Step 2: Divide every term by 3 to solve for y:
y = -2/3x + 4

So, the gradient (slope) of the line is -2/3 and the y-intercept is 4.

Knowee AI · Accepted Answer

To find the gradient and the y-intercept of the line, we first need to rearrange the equation into the slope-intercept form, which is y = mx + b, where m is the gradient (slope) and b is the y-intercept.

The given equation is 3y + 2x = 12.

Step 1: Subtract 2x from both sides to isolate y on one side of the equation:
3y = -2x + 12

Step 2: Divide every term by 3 to solve for y:
y = -2/3x + 4

So, the gradient (slope) of the line is -2/3 and the y-intercept is 4.

write down the gradient and the intercept on the y axis of the line 3 Y + 2x = 12

Question

Write down the gradient and the intercept on the y axis of the line $3Y + 2x = 12$

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