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Statement-I : 2R, 3S-Butane-2, 3-diol and 2S, 3R-Butane-2, 3-diol are enantiomers.           Statement-II : Enantiomers are differ in optical rotation

Question

Statement-I :

2R, 3S-Butane-2, 3-diol and 2S, 3R-Butane-2, 3-diol are enantiomers.

Statement-II :

Enantiomers differ in optical rotation.

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Solution

Statement-I: 2R, 3S-Butane-2, 3-diol and 2S, 3R-Butane-2, 3-diol are indeed enantiomers. Enantiomers are a type of stereoisomer, specifically, they are mirror images of each other that cannot be superimposed. In the case of 2R, 3S-Butane-2, 3-diol and 2S, 3R-Butane-2, 3-diol, the molecules have the same molecular formula and sequence of bonded atoms, but they differ in the three-dimensional orientations of their atoms in space. This is due to the presence of chiral centers at the 2nd and 3rd carbon atoms in the butane diol molecule.

Statement-II: Enantiomers do indeed differ in optical rotation. This is a characteristic property of enantiomers. When plane-polarized light is passed through a solution of an enantiomer, the plane of polarization is rotated. The direction in which the light is rotated is what differs between the two enantiomers. One enantiomer will rotate the light in a clockwise direction (dextrorotatory), and the other will rotate the light in a counterclockwise direction (levorotatory).

So, both statements are correct.

This problem has been solved

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