So, the optimal point is located at x = 9/5, y = -1/5, with λ = 8/5, and f(x, y) = 4. give these in 3dp

(-2,-8)is a point of f(x)=x³,      then point of f(x)=(x+5)³-3 is*(3,-5)(3,-11)(-8,-11)(-8,-5)

Which point lies on the line described by the equation below?y + 8 = 4(x - 5)A.(-5, -8)B.(5, 0)C.(5, 8)D.(4, -8)E.(5, -8)F.(4, 5)

.(3,-19)is point of y = 2f(x - 1)+2      then point of y = 2 f(¹/₃x - 1)+2 is*(-3,14)(-9,-14)(3,14)(9,-14)

Reflection  x axis of y=f(x+3,y)is*y=f(x+9,y)y=f(-x+3,y)y=-f(x+3,y)y=-f(-x+3,y)

If a function f(x)=(λ2−2λ−3)x4+(2λ+1)x3+21x+(8−λ) is monotonically increasing for all x∈R, then