To calculate the NMR frequency of a proton, we can use the formula:

ν = γB

where:
ν is the NMR frequency,
γ is the gyromagnetic ratio (which is equal to gn*μn/2π),
B is the magnetic field intensity.

Given:
gn = 5.585,
μn = 5.05×10−27 JT−1,
B = 1.4092 T,

we first calculate γ:

γ = gn*μn/2π = 5.585 * 5.05×10−27 JT−1 / 2π = 4.425×10^8 T^-1

Then we substitute γ and B into the formula to find ν:

ν = γB = 4.425×10^8 T^-1 * 1.4092 T = 623.6 MHz

So, the NMR frequency of the proton placed in a magnetic field of intensity 1.4092T is approximately 623.6 MHz.

Question

To calculate the NMR frequency of a proton, we can use the formula:

ν = γB

where:
ν is the NMR frequency,
γ is the gyromagnetic ratio (which is equal to gn*μn/2π),
B is the magnetic field intensity.

Given:
gn = 5.585,
μn = 5.05×10−27 JT−1,
B = 1.4092 T,

we first calculate γ:

γ = gn*μn/2π = 5.585 * 5.05×10−27 JT−1 / 2π = 4.425×10^8 T^-1

Then we substitute γ and B into the formula to find ν:

ν = γB = 4.425×10^8 T^-1 * 1.4092 T = 623.6 MHz

So, the NMR frequency of the proton placed in a magnetic field of intensity 1.4092T is approximately 623.6 MHz.

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