# The speed of the proton is 2.0 × 106 m s–1 and the magnetic field strength B is 0.35 T.(i) Show that the radius of the path is about 6 cm.

## Question

## Solution 1

To solve this problem, we need to use the formula for the radius of the path of a charged particle moving in a magnetic field, which is given by:

r = mv / (qB)

where:

- r is the radius of the path,
- m is the mass of the particle,
- v is the speed of the particle,
- q is the charge of the particle Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.

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