Two vectors are perpendicular to each other if their dot product is zero. The dot product of two vectors A = ai + bj + ck and B = di + ej + fk is given by:

A.B = ad + be + cf

Given vectors A = 2i + aj + k and B = 4i - 3j + 2k, their dot product is:

A.B = (2*4) + (a*-3) + (1*2) = 0

Solving this equation will give us the value of 'a':

8 - 3a + 2 = 0
-3a = -10
a = 10/3

So, none of the options A, B, C, D are correct. The value of 'a' is 10/3.

Question

Two vectors are perpendicular to each other if their dot product is zero. The dot product of two vectors A = ai + bj + ck and B = di + ej + fk is given by:

A.B = ad + be + cf

Given vectors A = 2i + aj + k and B = 4i - 3j + 2k, their dot product is:

A.B = (2*4) + (a*-3) + (1*2) = 0

Solving this equation will give us the value of 'a':

8 - 3a + 2 = 0
-3a = -10
a = 10/3

So, none of the options A, B, C, D are correct. The value of 'a' is 10/3.

Knowee AI · Accepted Answer

Two vectors are perpendicular to each other if their dot product is zero. The dot product of two vectors A = ai + bj + ck and B = di + ej + fk is given by:

A.B = ad + be + cf

Given vectors A = 2i + aj + k and B = 4i - 3j + 2k, their dot product is:

A.B = (2*4) + (a*-3) + (1*2) = 0

Solving this equation will give us the value of 'a':

8 - 3a + 2 = 0
-3a = -10
a = 10/3

So, none of the options A, B, C, D are correct. The value of 'a' is 10/3.

Find the value of 'a' if two vector A = 2i + aj +K & B = 4i - 3j + 2k are perpendicular to eachotherA. 20B. 15C. 10D. 5

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Find the value of 'a' if two vector

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