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What is the difference in mass between 1.5x1023 molecules of sulfur dioxide and 7.0 moles of hydrogen gas?

Question

What is the difference in mass between 1.5x10^23 molecules of sulfur dioxide and 7.0 moles of hydrogen gas?

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Solution

To answer this question, we need to know the molar mass of sulfur dioxide (SO2) and hydrogen gas (H2).

  1. The molar mass of SO2 is approximately 64.07 g/mol (32.07 g/mol for S and 16.00 g/mol for each O).
  2. The molar mass of H2 is approximately 2.02 g/mol (1.01 g/mol for each H).

Next, we need to convert the number of molecules to moles for SO2.

  1. Avogadro's number tells us that there are approximately 6.022 x 10^23 molecules in one mole. So, 1.5 x 10^23 molecules of SO2 is (1.5 x 10^23) / (6.022 x 10^23) = 0.249 moles.

Now we can find the mass of each substance.

  1. The mass of SO2 is (0.249 moles) x (64.07 g/mol) = 15.97 g.
  2. The mass of H2 is (7.0 moles) x (2.02 g/mol) = 14.14 g.

Finally, subtract the mass of H2 from the mass of SO2 to find the difference.

  1. The difference in mass is 15.97 g - 14.14 g = 1.83 g.

So, there is a difference of 1.83 grams between 1.5 x 10^23 molecules of sulfur dioxide and 7.0 moles of hydrogen gas.

This problem has been solved

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