A sample of ammonia weighs 4 g. What massof sulphur dioxide contains the same numberof molecules as are in 4 g of ammonia?

To find the mass of sulfur dioxide that contains the same number of molecules as 4 g of ammonia, we need to use the concept of molar mass and Avogadro's number.

1. Determine the molar mass of ammonia (NH3). The molar mass of nitrogen (N) is 14.01 g/mol, and the molar mass of hydrogen (H) is 1.01 g/mol. Since ammonia has three hydrogen atoms, the molar mass of ammonia is: Molar mass of ammonia (NH3) = (1.01 g/mol * 3) + 14.01 g/mol = 17.03 g/mol

2. Calculate the number of moles of ammonia in 4 g. To do this, divide the mass of ammonia by its molar mass: Moles of ammonia = Mass of ammonia / Molar mass of ammonia = 4 g / 17.03 g/mol ≈ 0.235 mol

3. Use the mole ratio between ammonia and sulfur dioxide to find the mass of sulfur dioxide. The balanced chemical equation for the reaction between ammonia and sulfur dioxide is: 2 NH3 + 3 SO2 → 3 H2O + N2 + 3 S

   From the equation, we can see that 2 moles of ammonia react with 3 moles of sulfur dioxide. Therefore, the mole ratio is: 2 moles of ammonia : 3 moles of sulfur dioxide

   Since we have 0.235 moles of ammonia, we can calculate the moles of sulfur dioxide using the mole ratio: Moles of sulfur dioxide = (3 moles of sulfur dioxide / 2 moles of ammonia) * 0.235 mol = 0.3525 mol

4. Finally, calculate the mass of sulfur dioxide using its molar mass. The molar mass of sulfur dioxide (SO2) is 64.06 g/mol: Mass of sulfur dioxide = Moles of sulfur dioxide * Molar mass of sulfur dioxide = 0.3525 mol * 64.06 g/mol ≈ 22.6 g

Therefore, the mass of sulfur dioxide that contains the same number of molecules as 4 g of ammonia is approximately 22.6 g.