Ksp of Zr3(PO4)4 in terms of solubility (S) is :-108 S74 S36912 S7None of these

The solubility product constant, Ksp, is a measure of the solubility of a compound. It is calculated by multiplying the concentrations of the ions that make up the compound.

For the compound Zr3(PO4)4, it dissociates in water as follows:

Zr3(PO4)4(s) ⇌ 3Zr4+(aq) + 4PO43-(aq)

The solubility (S) of Zr3(PO4)4 is the concentration of Zr3(PO4)4 that dissolves to form its ions.

The Ksp expression for this reaction is:

Ksp = [Zr4+]^3 * [PO43-]^4

Since each Zr3(PO4)4 produces 3 Zr4+ ions and 4 PO43- ions, we can express the concentrations of these ions in terms of S:

[Zr4+] = 3S [PO43-] = 4S

Substituting these into the Ksp expression gives:

Ksp = (3S)^3 * (4S)^4 Ksp = 108S^3 * 256S^4 Ksp = 27648S^7

So, the Ksp of Zr3(PO4)4 in terms of solubility (S) is 27648S^7. Therefore, none of the given options are correct.