Compute the margin of error at a 95% confidence level. (Round final answer to 2 decimal places.)

To compute the margin of error at a 95% confidence level, you need to know the standard deviation of your sample and the sample size. The formula for the margin of error is:

Margin of Error = Z * (Standard Deviation / sqrt(Sample Size))

Where:

• Z is the Z-value from the Z-table which corresponds to the desired confidence level. For a 95% confidence level, the Z-value is approximately 1.96.
• Standard Deviation is the standard deviation of your sample.
• sqrt(Sample Size) is the square root of your sample size.

Without these values, I can't compute the margin of error. Could you please provide them?