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A 98% confidence interval is found to be (32, 42). What is the margin of error?A.10B.9.8C.4.9D.5SUBMITarrow_backPREVIOUS

Question

A 98% confidence interval is found to be (32, 42). What is the margin of error?

A. 10
B. 9.8
C. 4.9
D. 5

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Solution

1. ### Break Down the Problem

To find the margin of error for a confidence interval, we can use the formula: Margin of Error=Upper LimitLower Limit2 \text{Margin of Error} = \frac{\text{Upper Limit} - \text{Lower Limit}}{2}

2. ### Relevant Concepts

From the given confidence interval (32, 42):

  • Lower Limit = 32
  • Upper Limit = 42

3. ### Analysis and Detail

Using the margin of error formula: Margin of Error=42322=102=5 \text{Margin of Error} = \frac{42 - 32}{2} = \frac{10}{2} = 5

4. ### Verify and Summarize

The calculated margin of error is consistent with the formula applied. Therefore, everything checks out.

Final Answer

The margin of error is 5. Thus, the correct option is D. 5.

This problem has been solved

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