Understanding Unary operators#include <stdio.h>void main() { int a = 10, b; b = a++ + ++a; printf("%d %d\n", a, b);}What is the a = b =

Question

#include &lt;stdio.h&gt;

void main() {
	int a = 10, b;
	b = a++ + ++a;
	printf(&quot;%d %d\n&quot;, a, b);
}

What is the
a =
b =

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The code you provided is written in C language and it's about understanding unary operators, specifically the increment operator (++).

Here's how it works:

int a = 10, b; This line declares two integer variables, a and b, and initializes a to 10.
b = a++ + ++a; This line uses the increment operator in two different ways. a++ is a post-increment operation, which means it returns the value of a before it adds 1 to a. ++a is a pre-increment operation, which means it adds 1 to a before it returns the value. So, here's how it works:
- a++ returns 10 (the original value of a), but a becomes 11 after this operation.
- ++a adds 1 to the current value of a (which is now 11), making a 12, and then returns 12.
- Therefore, b is assigned the value of 10 (from a++) plus 12 (from ++a), which is 22.
printf("%d %d\n", a, b); This line prints the values of a and b, which are 12 and 22, respectively.

So, a = 12 and b = 22.

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