How many ordered pairs of integers (x, y) satisfy the equation x2 + xy + y2 = x2y2
Question
Solution 1
To solve this problem, we need to find the ordered pairs of integers (x, y) that satisfy the equation x^2 + xy + y^2 = x^2y^2.
Step 1: Rewrite the equation to make it easier to solve.
x^2 + xy + y^2 - x^2y^2 = 0
Step 2: Factor the equation.
x^2(1 - y^2) + xy + y^2 = 0
Step 3: Set each factor Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study prob
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solv
Similar Questions
How many ordered pairs of integers (x, y) satisfy the equation x2 + xy + y2 = x2y2
How many ordered pairs satisfy the system of equations shown?y = x2-3x-10y=(x+2)(x-5)
x yy x x= 2 + 5= (2 − 3)( + 9)How many ordered pairs x y( , ) satisfy the system ofequations shown above?A) 0B) 1C) 2D) Infinitely many
Defined that x#y = x2 + y2 - xy, then 3#(2#4) = – 117 117 171 -171 None of these
AF(x,y) = ∫ex^2[x+y]dyBF(x,y) = ∫ ex^2[x - y] dyCF(x,y) = ∫ ex^2)[x2 + y2] dyDF(x,y) = ∫ ex^2[x2 – y2] dy