How many chromosomes does an individual with Turner syndrome have?n + 12n - 12n + 1n - 1

1. Break Down the Problem

We need to calculate the total number of chromosomes represented by the expression $n + 12n - 12n + 1n - 1$.

2. Relevant Concepts

Turner syndrome typically results from a complete or partial absence of one of the two X chromosomes in females. Most individuals with Turner syndrome have 45 chromosomes, which can be represented as having one X chromosome (45,X) instead of the typical 46.

3. Analysis and Detail

Let’s simplify the expression step by step:

1. Combine the like terms: $n + 12n - 12n + 1n - 1 = (1n + 12n - 12n + 1n) - 1$
2. This becomes: $(1n + 1n) - 1 = 2n - 1$

4. Verify and Summarize

Now we see that the expression simplifies to $2n - 1$.

For typical values of $n$:

• In human cells, $n$ is typically 23 (the number of chromosomes in a haploid set, like sperm or egg).
• Therefore, substituting $n = 23$: $2(23) - 1 = 46 - 1 = 45$

Final Answer

An individual with Turner syndrome has 45 chromosomes, which corresponds to the expression $2n - 1$ when $n$ is taken as 23.