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What is the value of Variable A after the execution of fowling code?int a=5;int A=0;for(int i=0;i<=a;i++){A=A+i;}10515-10

Question

What is the value of Variable A after the execution of the following code?

int a = 5;
int A = 0;
for(int i = 0; i &lt;= a; i++) {
    A = A + i;
}

10515-10

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Solution

The value of variable A after the execution of the following code will be 15.

Here's the step by step explanation:

  1. Initialize a to 5 and A to 0.
  2. Start a for loop that runs from i = 0 to i = a (which is 5).
  3. In each iteration of the loop, add i to A.
  4. So, the loop will run as follows:
    • When i = 0, A = 0 + 0 = 0.
    • When i = 1, A = 0 + 1 = 1.
    • When i = 2, A = 1 + 2 = 3.
    • When i = 3, A = 3 + 3 = 6.
    • When i = 4, A = 6 + 4 = 10.
    • When i = 5, A = 10 + 5 = 15.
  5. So, after the loop finishes, the value of A is 15.

This problem has been solved

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