What is the value of a[1] after the following code is executed?int[] a = {0, 2, 4, 1, 3};for(int i = 0; i < a.length; i++)a[i] = a[(a[i] + 3) % a.length];0123
Question
What is the value of a[1]
after the following code is executed?
int[] a = {0, 2, 4, 1, 3};
for(int i = 0; i < a.length; i++)
a[i] = a[(a[i] + 3) % a.length];
0123
Solution
The given code is in Java. Let's break it down:
-
An integer array
a
is declared and initialized with the values{0, 2, 4, 1, 3}
. -
A for loop is set up to iterate over the length of the array
a
. -
Inside the loop, each element of the array
a
at indexi
is reassigned to the value of the element at the index(a[i] + 3) % a.length
.
Let's go through the loop:
-
For
i = 0
,a[0]
is reassigned toa[(0 + 3) % 5]
which isa[3]
. So,a[0]
becomes1
. -
For
i = 1
,a[1]
is reassigned toa[(2 + 3) % 5]
which isa[0]
. So,a[1]
becomes1
. -
For
i = 2
,a[2]
is reassigned toa[(4 + 3) % 5]
which isa[2]
. So,a[2]
remains4
. -
For
i = 3
,a[3]
is reassigned toa[(1 + 3) % 5]
which isa[4]
. So,a[3]
becomes3
. -
For
i = 4
,a[4]
is reassigned toa[(3 + 3) % 5]
which isa[1]
. So,a[4]
becomes1
.
So, after the code is executed, the array a
becomes {1, 1, 4, 3, 1}
.
Therefore, the value of a[1]
is 1
.
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