Calculate the power dissipated when a current of 4 mA flows through a resistance of 5 kΩ
Question
Calculate the power dissipated when a current of 4 mA flows through a resistance of 5 kΩ
Solution
Sure, to calculate the power dissipated in a resistor, we can use the formula P = I^2 * R, where P is the power, I is the current, and R is the resistance.
Step 1: Convert the current from milliamperes (mA) to amperes (A). 1 mA = 0.001 A, so 4 mA = 0.004 A.
Step 2: Convert the resistance from kilohms (kΩ) to ohms (Ω). 1 kΩ = 1000 Ω, so 5 kΩ = 5000 Ω.
Step 3: Substitute the values into the formula. P = (0.004 A)^2 * 5000 Ω = 0.000016 A^2 * 5000 Ω = 0.08 W.
So, the power dissipated when a current of 4 mA flows through a resistance of 5 kΩ is 0.08 Watts.
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