In the given figure, the emf of the cell is 2.2 V and if internal resistance is 0.6Ω. Calculate the power dissipated in the whole circuit :
Question
In the given figure, the emf of the cell is 2.2 V and if internal resistance is 0.6 Ω.
Calculate the power dissipated in the whole circuit:
Solution
To calculate the power dissipated in the whole circuit, we first need to find the total current flowing in the circuit.
Step 1: Calculate the total current (I) in the circuit.
The total current in the circuit can be calculated using Ohm's law, which states that the current is equal to the voltage (V) divided by the resistance (R). In this case, the total voltage is the emf of the cell (2.2 V) and the total resistance is the internal resistance (0.6 Ω).
So, I = V/R = 2.2 V / 0.6 Ω = 3.67 A
Step 2: Calculate the power (P) dissipated in the circuit.
The power dissipated in a circuit can be calculated using the formula P = I^2 * R, where I is the current and R is the resistance.
So, P = (3.67 A)^2 * 0.6 Ω = 8.08 W
Therefore, the power dissipated in the whole circuit is 8.08 W.
Similar Questions
If i is current through the circuit and E is EMF of battery then power P at which chemical energy of battery is dissipated isa.P=iEb.P=E/ic.P=Ei^2d.P=i/E
At 298K, the EMF of the cell: Mg(s) |Mg2+(Q)||Ag+(0.01)|Ag(s)is 3.022V. Calculate the value ‘Q’.(Given: EoMg2+/Mg = -2.37V and EoAg+/Ag = 0.80V)
The power dissipated in a conductor of resistivity ρ connected across a battery is directly proportional to Only one correct answerA.ρ2B.√ρρC.ρD.ρ–1
The EMF of the cell : Ni(s) | Ni2+ (1.0M) || Au 3+ (1.0M) | Au (s) is[ given EoNi2+/Ni -0.25V; E° Au3+ / Au = +1.50V ]
If 80. joules of electrical energy is dissipated by a 10.-ohm resistor in 2.0 seconds, the current in theresistor is
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.