A particle executing SHM has a maximum speed of 30 cm/s and angular frequency of 10 rad/s. Theamplitude of oscillation is
Question
A particle executing SHM has a maximum speed of 30 cm/s and angular frequency of 10 rad/s.
The amplitude of oscillation is ...
Solution
The amplitude of oscillation can be found using the formula for maximum speed in simple harmonic motion (SHM), which is given by Vmax = ωA, where Vmax is the maximum speed, ω is the angular frequency, and A is the amplitude.
Given that Vmax = 30 cm/s and ω = 10 rad/s, we can rearrange the formula to solve for A:
A = Vmax / ω
Substituting the given values:
A = 30 cm/s / 10 rad/s = 3 cm
So, the amplitude of oscillation is 3 cm.
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