What is the output of the following code?int arr[] = {1, 2, 3, 4, 5};int *p = arr;p++;printf("%d\n", *p);
Question
Solution 1
The output of the code will be 2.
Here's the step by step explanation:
-
An integer array
arr[]
is declared and initialized with the values{1, 2, 3, 4, 5}
. -
A pointer to an integer
*p
is declared and it is initialized to point to the first element of the arrayarr[]
. So,*p
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