in 96Y4+ the difference between electrons and neutronsnumbers in the ion is 22. How many electrons does A2+have? chemistry

The given isotope is 96Y4+. Yttrium (Y) has an atomic number of 39, which means it has 39 protons. In a neutral atom, the number of protons is equal to the number of electrons. However, this is an ion with a charge of +4, meaning it has lost 4 electrons. So, the number of electrons in 96Y4+ is 39 - 4 = 35.

The isotope's mass number is 96, which is the sum of protons and neutrons. So, the number of neutrons is 96 - 39 = 57.

The difference between the number of electrons and neutrons in 96Y4+ is 57 - 35 = 22, which matches the given information.

Now, for the ion A2+, we don't know what element A is, but we know it has lost 2 electrons to become a 2+ ion. Since the difference between the number of electrons and neutrons in A2+ is the same as in 96Y4+, A2+ must also have 35 electrons.