valuate S√x + 1√x dx.A. x + √x + CB. x + 2√x + CC. x − √x + CD. x − 2√x + CE. None of the previous

The integral of √x + 1/√x dx can be solved as follows:

First, we can rewrite the integral as ∫x^(1/2) dx + ∫x^(-1/2) dx.

Now, we can integrate each term separately using the power rule for integration, which states that the integral of x^n dx is (1/(n+1))x^(n+1), where n ≠ -1.

For the first term, n = 1/2, so the integral is (1/(1/2 + 1))x^(1/2 + 1) = 2/3 * x^(3/2).

For the second term, n = -1/2, so the integral is (1/(-1/2 + 1))x^(-1/2 + 1) = 2x^(1/2).

Therefore, the integral of √x + 1/√x dx is 2/3 * x^(3/2) + 2x^(1/2) + C, where C is the constant of integration.

So, the answer is not listed among the options A, B, C, D. Therefore, the answer is E. None of the previous.