valuate S√x + 1√x dx.A. x + √x + CB. x + 2√x + CC. x − √x + CD. x − 2√x + CE. None of the previous
Question
Solution 1
The integral of √x + 1/√x dx can be solved as follows:
First, we can rewrite the integral as ∫x^(1/2) dx + ∫x^(-1/2) dx.
Now, we can integrate each term separately using the power rule for integration, which states that the integral of x^n dx is (1/(n+1))x^(n+1), where n ≠ -1.
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