Separate 84 into two parts such that one part will be 12 less than twice the other.
Question
Separate 84 into two parts such that one part will be 12 less than twice the other.
Solution
Sure, let's solve this step by step:
Step 1: Let's denote the smaller part as x. Then the larger part would be 2x - 12 (which is 12 less than twice the smaller part).
Step 2: According to the problem, the sum of these two parts should be 84. So we can set up the following equation: x + 2x - 12 = 84.
Step 3: Simplify the equation: 3x - 12 = 84.
Step 4: Add 12 to both sides of the equation: 3x = 96.
Step 5: Divide both sides of the equation by 3: x = 32.
So, the smaller part is 32 and the larger part is 2*32 - 12 = 52.
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