When the diode is reverse biased with a voltage of 9V and Vbias=0.54V. So, the total potential will be A- 9.54 V B- 9 V C- 8.46 V D- 0.06 V

Problem Breakdown

1. Identify the situation: A diode is reverse biased with a voltage of 9V.
2. Determine the additional bias voltage $V_{bias} = 0.54V$.

Relevant Concepts

1. The total potential difference across the diode when reverse biased is calculated by subtracting $V_{bias}$ from the reverse voltage.
2. The relationship can be expressed as follows: $V_{total} = V_{reverse} - V_{bias}$

Analysis and Detail

1. Plugging in the values: $V_{total} = 9V - 0.54V$
2. Performing the calculation: $V_{total} = 9V - 0.54V = 8.46V$

Verify and Summarize

• The total voltage across the diode when reverse biased is $8.46V$.
• Verify the calculations: $9 - 0.54 = 8.46$
• This confirms that the calculations are correct.

Final Answer

The total potential is C - 8.46 V.