The potential at a point due to a positive charge of 100μC at a distance of 9m is104 V105 V106 VNone of these
Question
The potential at a point due to a positive charge of 100μC at a distance of 9m is
- 104 V
- 105 V
- 106 V
- None of these
Solution
The potential V at a point due to a charge Q at a distance r is given by the formula:
V = kQ/r
where:
- k is Coulomb's constant, approximately 9 x 10^9 Nm^2/C^2
- Q is the charge, in this case 100μC or 100 x 10^-6 C
- r is the distance, in this case 9m
Substituting these values into the formula gives:
V = (9 x 10^9 Nm^2/C^2) * (100 x 10^-6 C) / 9m
Solving this gives:
V = 9 x 10^3 V
So, the potential at the point due to the charge is 9000 V. Therefore, the correct answer is "None of these".
Similar Questions
The potential at a point due to a positive charge of 100μC at a distance of 9m is104 V105 V106 VNone of these
The potential at a point due to a charge of 4×10-7C located 10cm away is: Use: K=9×109 Nm2/C2.a.4.5×104Vb.3.6×105Vc.3.6×104Vd.4.5×105V
Determine the electric potential produced by a point charge of 6.80x10-7 C at a distance of 2.60 cm.
Two point charges are 10 cm apart and their combined charge is 9μC. Ifthey repel each other with a force of 18N, then calculate the magnitude ofeach charge
A point charge of 5 C is moved from a point of –10 V to a point of V0 volt and the work done by external force in the process is 100 J, the value of V0 is
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.