Visible light travels through the output phosphor at 1.6 × 108 m/s. What is the refractive index of the material?A.1.9B.1.1C.0.88D.0.53
Question
Visible light travels through the output phosphor at 1.6 × 10^8 m/s. What is the refractive index of the material?
- A. 1.9
- B. 1.1
- C. 0.88
- D. 0.53
Solution
The refractive index of a material is calculated by the formula:
n = c/v
where: n is the refractive index, c is the speed of light in a vacuum (approximately 3.00 x 10^8 m/s), and v is the speed of light in the material.
Given that the speed of light in the output phosphor is 1.6 x 10^8 m/s, we can substitute these values into the formula:
n = (3.00 x 10^8 m/s) / (1.6 x 10^8 m/s) = 1.875
The answer closest to this is 1.9 (A).
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