Write an program in C/C++, to read an expression in Inform and Display the same in Pofstfix Form

Sure, here is a step-by-step guide to write a program in C/C++ to read an expression in Inform and display it in postfix form:

1. Start by including the necessary header files for input/output operations and string manipulation:

#include <stdio.h>
#include <string.h>
#include <ctype.h>

2. Define a function to check if a character is an operator:

int isOperator(char ch) {
    if (ch == '+' || ch == '-' || ch == '*' || ch == '/')
        return 1;
    return 0;
}

3. Define a function to convert the infix expression to postfix form:

void infixToPostfix(char infix[], char postfix[]) {
    int i, j;
    char stack[100];
    int top = -1;

    // Iterate through each character in the infix expression
    for (i = 0, j = 0; infix[i] != '\0'; i++) {
        // If the character is an operand, add it to the postfix expression
        if (isalnum(infix[i])) {
            postfix[j++] = infix[i];
        }
        // If the character is an opening parenthesis, push it to the stack
        else if (infix[i] == '(') {
            stack[++top] = infix[i];
        }
        // If the character is a closing parenthesis, pop operators from the stack and add them to the postfix expression until an opening parenthesis is encountered
        else if (infix[i] == ')') {
            while (top != -1 && stack[top] != '(') {
                postfix[j++] = stack[top--];
            }
            // Pop the opening parenthesis from the stack
            if (top != -1 && stack[top] == '(') {
                top--;
            }
        }
        // If the character is an operator, pop operators from the stack and add them to the postfix expression until an operator with lower precedence or an opening parenthesis is encountered
        else if (isOperator(infix[i])) {
            while (top != -1 && stack[top] != '(' && infix[i] <= stack[top]) {
                postfix[j++] = stack[top--];
            }
            // Push the current operator to the stack
            stack[++top] = infix[i];
        }
    }

    // Pop any remaining operators from the stack and add them to the postfix expression
    while (top != -1 && stack[top] != '(') {
        postfix[j++] = stack[top--];
    }

    // Add null character at the end of the postfix expression
    postfix[j] = '\0';
}

4. Define the main function to read the infix expression from the user and display it in postfix form:

int main() {
    char infix[100], postfix[100];

    // Read the infix expression from the user
    printf("Enter the infix expression: ");
    scanf("%s", infix);

    // Convert the infix expression to postfix form
    infixToPostfix(infix, postfix);

    // Display the postfix expression
    printf("Postfix expression: %s\n", postfix);

    return 0;
}

5. Compile and run the program. Enter the infix expression when prompted, and the program will display the corresponding postfix expression.

Note: This program assumes that the infix expression is valid and does not handle errors such as mismatched parentheses or invalid operators.