Complete the simplification below by finding the values of the capitalised pronumerals.𝑋 is a negative number.  6(2𝑎−4𝑐)−6(6𝑎−4𝑏)+3(4𝑏−8𝑐)4=𝑋(2𝑎+𝑌𝑏+𝑍𝑐) 𝑋=𝑌=

The question seems to be incomplete. You have asked for the values of X, Y, and Z but you have not provided any specific values for a, b, and c.

However, we can simplify the equation and express Y and Z in terms of X.

First, let's simplify the left side of the equation:

6(2a-4c) - 6(6a-4b) + 3(4b-8c) = 12a - 24c - 36a + 24b + 12b - 24c This simplifies to: -24a + 36b - 48c

Now, let's equate this to the right side of the equation:

-24a + 36b - 48c = X(2a + Yb + Zc)

Now, we can compare the coefficients on both sides of the equation to find the values of X, Y, and Z.

Comparing the coefficients of 'a', we get X*2 = -24, so X = -24/2 = -12.

Comparing the coefficients of 'b', we get X*Y = 36, so Y = 36/X = 36/-12 = -3.

Comparing the coefficients of 'c', we get X*Z = -48, so Z = -48/X = -48/-12 = 4.

So, X = -12, Y = -3, and Z = 4.