How many grams in 1.75 mol of NH4Br? (one-step problem) a6.02 g b171 g c0.0179 g d97.9 g e55.9 g

1. Break Down the Problem

To find out how many grams are in 1.75 moles of NH₄Br, we need to do the following:

1. Determine the molar mass of NH₄Br.
2. Multiply the number of moles (1.75) by the molar mass.

2. Relevant Concepts

The molar mass of a compound is calculated by adding the atomic masses of its components.

• The atomic masses from the periodic table are approximately:
  • Nitrogen (N): 14.01 g/mol
  • Hydrogen (H): 1.01 g/mol (there are 4 H atoms in NH₄)
  • Bromine (Br): 79.90 g/mol

3. Analysis and Detail

Calculate the molar mass of NH₄Br:

$\text{Molar Mass of NH}_4\text{Br} = (1 \cdot 14.01 \, \text{g/mol}) + (4 \cdot 1.01 \, \text{g/mol}) + (1 \cdot 79.90 \, \text{g/mol})$

Calculating each component:

• N: $1 \cdot 14.01 = 14.01\, \text{g/mol}$
• H: $4 \cdot 1.01 = 4.04\, \text{g/mol}$
• Br: $1 \cdot 79.90 = 79.90\, \text{g/mol}$

Now, summing these values: $\text{Molar Mass of NH}_4\text{Br} = 14.01 + 4.04 + 79.90 = 97.95\, \text{g/mol}$

Now, convert moles to grams: $\text{Mass} = \text{moles} \times \text{molar mass} = 1.75 \, \text{mol} \times 97.95 \, \text{g/mol}$

4. Verify and Summarize

Calculating the total mass: $\text{Mass} = 1.75 \times 97.95 \approx 171.3\, \text{g}$

Thus, rounding to two decimal places, the total mass of 1.75 moles of NH₄Br is approximately 171 g.

Final Answer

171 g