What is the solution to 4(y−3)+19=8(2y+3)+74(𝑦-3)+19=8(2𝑦+3)+7? A. −12-12 B. 1212 C. −2-2 D. 2
Question
What is the solution to
4(y−3)+19=8(2y+3)+74(y-3)+19=8(2y+3)+7?
A. −12
B. 12
C. −2
D. 2
Solution
Let's solve the equation step by step:
First, distribute the numbers outside the parentheses:
4(y - 3) + 19 = 8(2y + 3) + 7 becomes 4y - 12 + 19 = 16y + 24 + 7
Simplify the equation:
4y + 7 = 16y + 31
Subtract 4y from both sides:
7 = 12y + 31
Subtract 31 from both sides:
-24 = 12y
Finally, divide both sides by 12 to solve for y:
y = -24 / 12 = -2
So, the solution to the equation is -2 (Option C).
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