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a = Trueb = Falsec = False if not a or b:    print (1)elif not a or not b and c:    print (2)elif not a or b or not b and a:    print (3)else:    print (4)

Question


a = True
b = False
c = False

if not a or b:
    print (1)
elif not a or not b and c:
    print (2)
elif not a or b or not b and a:
    print (3)
else:
    print (4)
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Solution

The given code is written in Python. Let's break it down:

  1. The variables a, b, and c are assigned the boolean values True, False, and False respectively.

  2. The if statement checks if not a or b is True. Since a is True, not a becomes False. And b is False. So, False or False results in False. Hence, the if condition is False and it does not print 1.

  3. The elif statement checks if not a or not b and c is True. Again, not a is False, not b is True and c is False. So, False or True and False results in False. Hence, the elif condition is False and it does not print 2.

  4. The next elif statement checks if not a or b or not b and a is True. Here, not a is False, b is False, not b is True and a is True. So, False or False or True and True results in True. Hence, the elif condition is True and it prints 3.

  5. The else statement would execute if all the above conditions were False. But since the last elif condition was True, it does not execute and does not print 4.

So, the output of this code will be 3.

This problem has been solved

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