a = Trueb = Falsec = False if not a or b: print (1)elif not a or not b and c: print (2)elif not a or b or not b and a: print (3)else: print (4)
Question
a = True
b = False
c = False
if not a or b:
print (1)
elif not a or not b and c:
print (2)
elif not a or b or not b and a:
print (3)
else:
print (4)
Solution
The given code is written in Python. Let's break it down:
-
The variables
a
,b
, andc
are assigned the boolean valuesTrue
,False
, andFalse
respectively. -
The
if
statement checks ifnot a or b
isTrue
. Sincea
isTrue
,not a
becomesFalse
. Andb
isFalse
. So,False or False
results inFalse
. Hence, theif
condition isFalse
and it does not print1
. -
The
elif
statement checks ifnot a or not b and c
isTrue
. Again,not a
isFalse
,not b
isTrue
andc
isFalse
. So,False or True and False
results inFalse
. Hence, theelif
condition isFalse
and it does not print2
. -
The next
elif
statement checks ifnot a or b or not b and a
isTrue
. Here,not a
isFalse
,b
isFalse
,not b
isTrue
anda
isTrue
. So,False or False or True and True
results inTrue
. Hence, theelif
condition isTrue
and it prints3
. -
The
else
statement would execute if all the above conditions wereFalse
. But since the lastelif
condition wasTrue
, it does not execute and does not print4
.
So, the output of this code will be 3
.
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