The given code is written in Python. Let's break it down step by step:

1. `a=0` and `b=6` are simple variable assignments. `a` is assigned the value `0` and `b` is assigned the value `6`.

2. `x=(a&b)|(a&a | a&b)` is a bitwise operation. The `&` operator performs a bitwise AND operation, and the `|` operator performs a bitwise OR operation.

- `a&b` is `0&6` which results in `0` because the bitwise AND operation between any number and `0` always results in `0`.
- `a&a` is `0&0` which results in `0`.
- `a&b` is again `0&6` which results in `0`.
- So, `x` becomes `(0 | 0 | 0)` which is `0`.

3. `y=not(x)` is a logical NOT operation. The `not` operator in Python returns `True` if the operand is `False`, and `False` if the operand is `True`. Since `x` is `0`, which is considered `False` in a boolean context, `not(x)` returns `True`. So, `y` is `True`.

4. `print(y)` prints the value of `y`, which is `True`.

So, the output of the program will be `True`.

Question

The given code is written in Python. Let's break it down step by step:

1. `a=0` and `b=6` are simple variable assignments. `a` is assigned the value `0` and `b` is assigned the value `6`.

2. `x=(a&b)|(a&a | a&b)` is a bitwise operation. The `&` operator performs a bitwise AND operation, and the `|` operator performs a bitwise OR operation.

- `a&b` is `0&6` which results in `0` because the bitwise AND operation between any number and `0` always results in `0`.
   - `a&a` is `0&0` which results in `0`.
   - `a&b` is again `0&6` which results in `0`.
   - So, `x` becomes `(0 | 0 | 0)` which is `0`.

3. `y=not(x)` is a logical NOT operation. The `not` operator in Python returns `True` if the operand is `False`, and `False` if the operand is `True`. Since `x` is `0`, which is considered `False` in a boolean context, `not(x)` returns `True`. So, `y` is `True`.

4. `print(y)` prints the value of `y`, which is `True`.

So, the output of the program will be `True`.

Knowee AI · Accepted Answer

The given code is written in Python. Let's break it down step by step:

1. `a=0` and `b=6` are simple variable assignments. `a` is assigned the value `0` and `b` is assigned the value `6`.

2. `x=(a&b)|(a&a | a&b)` is a bitwise operation. The `&` operator performs a bitwise AND operation, and the `|` operator performs a bitwise OR operation.

- `a&b` is `0&6` which results in `0` because the bitwise AND operation between any number and `0` always results in `0`.
   - `a&a` is `0&0` which results in `0`.
   - `a&b` is again `0&6` which results in `0`.
   - So, `x` becomes `(0 | 0 | 0)` which is `0`.

3. `y=not(x)` is a logical NOT operation. The `not` operator in Python returns `True` if the operand is `False`, and `False` if the operand is `True`. Since `x` is `0`, which is considered `False` in a boolean context, `not(x)` returns `True`. So, `y` is `True`.

4. `print(y)` prints the value of `y`, which is `True`.

So, the output of the program will be `True`.

What will be the output of the following program on execution?a=0b=6x=(a&b)|(a&a | a&b)y=not(x)print(y)6True0False

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What will be the output of the following program on execution?

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