What will be the output of the following program on execution?a=0b=6x=(a&b)|(a&a | a&b)y=not(x)print(y)6True0False

The given code is written in Python. Let's break it down step by step:

1. a=0 and b=6 are simple variable assignments. a is assigned the value 0 and b is assigned the value 6.

2. x=(a&b)|(a&a | a&b) is a bitwise operation. The & operator performs a bitwise AND operation, and the | operator performs a bitwise OR operation.

   • a&b is 0&6 which results in 0 because the bitwise AND operation between any number and 0 always results in 0.
   • a&a is 0&0 which results in 0.
   • a&b is again 0&6 which results in 0.
   • So, x becomes (0 | 0 | 0) which is 0.

3. y=not(x) is a logical NOT operation. The not operator in Python returns True if the operand is False, and False if the operand is True. Since x is 0, which is considered False in a boolean context, not(x) returns True. So, y is True.

4. print(y) prints the value of y, which is True.

So, the output of the program will be True.