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Solve the following quadratic equation for all values of xx in simplest form.4, left bracket, 2, x, minus, 2, right bracket, squared, equals, 164(2x−2) 2 =16

Question

Solve the following quadratic equation for all values of xx in simplest form.

4(2x−2)2=164(2x−2) 4(2x - 2)^2 = 164(2x - 2)

(2x−2)2=16 (2x - 2)^2 = 16

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Solution

The equation you provided seems to have a formatting issue. However, I'll assume you meant the equation to be:

4*(2x - 2)^2 = 16

Here are the steps to solve it:

  1. Divide both sides of the equation by 4 to simplify:

    (2x - 2)^2 = 4

  2. Take the square root of both sides:

    2x - 2 = ± √4

  3. Simplify the right side:

    2x - 2 = ± 2

  4. Solve for x by adding 2 to both sides:

    2x = 2 ± 2

  5. Finally, divide by 2 to isolate x:

    x = 1 ± 1

So, the solutions are x = 2 and x = 0.

This problem has been solved

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