Two identical quadrants were overlapped in a square of side 2 cm. The radius of the quadrants were 6 cm. Find the area of the figure. Take π as 3.14.

Question

Two identical quadrants were overlapped in a square of side 2 cm. The radius of the quadrants were 6 cm. Find the area of the figure. Take π as 3.14.
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Solution 1

Sure, let's solve this step by step:

Step 1: First, let's find the area of the square. The formula for the area of a square is side^2. So, the area of the square is 2 cm * 2 cm = 4 cm^2.

Step 2: Now, let's find the area of one quadrant. The formula for the area of a circle is πr^2. Since a quadran Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study prob

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