Hannah is cycling down a hill. Her velocity increases by 1 m/s1 m/s in 3 s3 s. Calculate Hannah's acceleration: 𝑎=Δ𝑣Δ𝑡a= ΔtΔv​

1. Break Down the Problem

We need to find Hannah's acceleration given the change in velocity and the time interval over which this change occurs. The formula for acceleration $a$ is given by: $a = \frac{\Delta v}{\Delta t}$ where:

• $\Delta v$ = change in velocity
• $\Delta t$ = change in time

2. Relevant Concepts

In this case:

• $\Delta v = 1 \, \text{m/s}$ (the increase in velocity),
• $\Delta t = 3 \, \text{s}$ (the time interval).

3. Analysis and Detail

Substituting the known values into the formula: $a = \frac{1 \, \text{m/s}}{3 \, \text{s}}$

4. Verify and Summarize

Calculating the result: $a = \frac{1}{3} \, \text{m/s}^2 \approx 0.333 \, \text{m/s}^2$ This means Hannah's acceleration down the hill is approximately $0.333 \, \text{m/s}^2$.

Final Answer

Hannah's acceleration is $\frac{1}{3} \, \text{m/s}^2$ or approximately $0.333 \, \text{m/s}^2$.