The velocity changes from 35m/s to 60m/s in 3 seconds. What is its acceleration?

1. Break Down the Problem

To find the acceleration, we need to determine the change in velocity and the time over which this change occurs.

2. Relevant Concepts

The formula to calculate acceleration ($a$) is given by: $a = \frac{\Delta v}{\Delta t}$ where:

• $\Delta v$ is the change in velocity
• $\Delta t$ is the change in time

3. Analysis and Detail

1. Calculate the change in velocity ($\Delta v$): $\Delta v = v_f - v_i$ where:

   • $v_f = 60 \, \text{m/s}$ (final velocity)
   • $v_i = 35 \, \text{m/s}$ (initial velocity)

   Substituting the values: $\Delta v = 60 \, \text{m/s} - 35 \, \text{m/s} = 25 \, \text{m/s}$

2. Identify the time interval ($\Delta t$): $\Delta t = 3 \, \text{s}$

3. Calculate the acceleration ($a$): $a = \frac{\Delta v}{\Delta t} = \frac{25 \, \text{m/s}}{3 \, \text{s}} \approx 8.33 \, \text{m/s}^2$

4. Verify and Summarize

The calculations show that the change in velocity is 25 m/s over a period of 3 seconds, leading us to an acceleration of approximately 8.33 m/s².

Final Answer

The acceleration is approximately $8.33 \, \text{m/s}^2$.