Assuming that the lamps are connected in series, the potential difference (voltage) will be divided equally among them.

Step 1: Identify the total voltage across the circuit, which is given as 6V.

Step 2: Identify the number of components (lamps) in the series circuit, which is given as 3.

Step 3: Divide the total voltage by the number of components to find the voltage across each component.

So, 6V ÷ 3 lamps = 2V per lamp.

Therefore, the potential difference across each lamp is 2 volts.

Question

Assuming that the lamps are connected in series, the potential difference (voltage) will be divided equally among them.

Step 1: Identify the total voltage across the circuit, which is given as 6V.

Step 2: Identify the number of components (lamps) in the series circuit, which is given as 3.

Step 3: Divide the total voltage by the number of components to find the voltage across each component.

So, 6V ÷ 3 lamps = 2V per lamp.

Therefore, the potential difference across each lamp is 2 volts.

Knowee AI · Accepted Answer

Assuming that the lamps are connected in series, the potential difference (voltage) will be divided equally among them.

Step 1: Identify the total voltage across the circuit, which is given as 6V.

Step 2: Identify the number of components (lamps) in the series circuit, which is given as 3.

Step 3: Divide the total voltage by the number of components to find the voltage across each component.

So, 6V ÷ 3 lamps = 2V per lamp.

Therefore, the potential difference across each lamp is 2 volts.

If the potential difference across the battery is 6V and there are 3 lamps - what is the potential difference (in volts) of each lamp?