Obtain the Fourier series of the function f x given as follows:𝑓(𝑥) = { 𝑥, 0 ≤ 𝑥 ≤ 𝜋0, 𝜋 ≤ 𝑥 ≤ 2𝜋 }
Question
Obtain the Fourier series of the function
Given as follows:
Solution
To obtain the Fourier series of the function f(x), we need to find the coefficients of the sine and cosine terms.
Step 1: Determine the period of the function. In this case, the function is periodic with a period of 2π since it repeats every 2π units.
Step 2: Find the average value of the function over one period. Since f(x) is defined differently for different intervals, we need to calculate the average value separately for each interval.
For the interval 0 ≤ x ≤ π, the function f(x) is equal to x. To find the average value, we integrate f(x) over this interval and divide by the length of the interval: average value = (1/π) ∫[0,π] x dx = (1/π) [x^2/2] from 0 to π = (1/π) (π^2/2) = π/2
For the interval π ≤ x ≤ 2π, the function f(x) is equal to 0. The average value over this interval is simply 0.
Step 3: Calculate the coefficients of the sine and cosine terms using the formulas:
a0 = average value = π/2 an = (2/π) ∫[0,π] x cos(nωx) dx, for n > 0 bn = (2/π) ∫[0,π] x sin(nωx) dx, for n > 0
where ω = 2π/T is the angular frequency and T is the period.
For the cosine terms: a0 = π/2 an = (2/π) ∫[0,π] x cos(nπx/π) dx = (2/π) ∫[0,π] x cos(nx) dx = (2/π) [x sin(nx)/n] from 0 to π = (2/π) (π sin(nπ)/n) = 2 sin(nπ)/n
For the sine terms: bn = (2/π) ∫[0,π] x sin(nπx/π) dx = (2/π) ∫[0,π] x sin(nx) dx = -(2/π) [x cos(nx)/n] from 0 to π = -(2/π) (π cos(nπ)/n) = -2 cos(nπ)/n
Step 4: Write the Fourier series using the calculated coefficients. Since the function is defined differently for different intervals, we need to write the series separately for each interval.
For the interval 0 ≤ x ≤ π, the Fourier series is: f(x) = a0/2 + ∑[n=1,∞] an cos(nωx) + bn sin(nωx) = (π/4) + ∑[n=1,∞] (2 sin(nπ)/n) cos(nx) - (2 cos(nπ)/n) sin(nx)
For the interval π ≤ x ≤ 2π, the Fourier series is simply 0.
So, the Fourier series of the function f(x) is given by: f(x) = (π/4) + ∑[n=1,∞] (2 sin(nπ)/n) cos(nx) - (2 cos(nπ)/n) sin(nx) for 0 ≤ x ≤ π 0 for π ≤ x ≤ 2π
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