A 275 mL sample of argon had its pressure changed from 150kPa to 260 kPa. What is its new volume

This problem can be solved using Boyle's Law, which states that the pressure and volume of a gas have an inverse relationship when temperature is held constant. In other words, P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.

Here's how to solve it:

1. Identify the initial pressure (P1), initial volume (V1), and final pressure (P2). In this case, P1 = 150 kPa, V1 = 275 mL, and P2 = 260 kPa.

2. Plug these values into the Boyle's Law equation and solve for V2 (the final volume).

   So, 150 kPa * 275 mL = 260 kPa * V2

3. Solve for V2 by dividing both sides of the equation by 260 kPa:

   V2 = (150 kPa * 275 mL) / 260 kPa

4. Calculate the value to find V2.

   V2 = 158.65 mL

So, the new volume of the argon sample when the pressure is changed from 150 kPa to 260 kPa is approximately 158.65 mL.