consider a stand of eucalyptus, trees that are on average 30cm in diameter and spaced on a regular 3m grid. find the spacing factor
Question
Consider a stand of eucalyptus, trees that are on average 30cm in diameter and spaced on a regular 3m grid. Find the spacing factor.
Solution
The spacing factor can be calculated using the formula:
Spacing Factor = (Spacing between trees)^2 / (Tree Diameter)
Given that the trees are spaced on a regular 3m grid and the average diameter of the trees is 30cm (or 0.3m), we can substitute these values into the formula:
Spacing Factor = (3m)^2 / (0.3m) Spacing Factor = 9m^2 / 0.3m Spacing Factor = 30m
So, the spacing factor for the stand of eucalyptus trees is 30m.
Similar Questions
3 trees are located is a sample plot of 15m X 15m. their dbh are as under:dbh= 25cm, 30cm, 35cm find the stand basal area in sq m per Ha
The length of a belt of trees on a map is 3.5 cm and its real length is 200 m.Express this as a ratio.
for a tree with dbh= 45.6cm, height= 27m and total stem volume of 1.78cum, the artificial form factor of the tree is:
A balanced binary tree with m elements will have height ______________ . A. 2m B. 2m C. logm 2 D. none of the above E. log2 m
In a BST, what is the minimum number of nodes required to form a tree with a height of 3?3478
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.