The angle of elevation from a car to a tower is 32°. The tower is 150 ft. tall. How far is the car from the tower?*240.05 feet286.60 feet
Question
The angle of elevation from a car to a tower is 32°. The tower is 150 ft. tall. How far is the car from the tower?
- 240.05 feet
- 286.60 feet
Solution
To solve this problem, we can use the tangent of the angle of elevation, which is the ratio of the opposite side (height of the tower) to the adjacent side (distance from the car to the tower).
Here are the steps:
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We know the angle of elevation (32°) and the height of the tower (150 ft).
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We set up the equation for the tangent of the angle of elevation: tan(32°) = 150 ft / d, where d is the distance from the car to the tower.
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We solve this equation for d: d = 150 ft / tan(32°).
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Using a calculator, we find that tan(32°) is approximately 0.6248693519093273.
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Therefore, d = 150 ft / 0.6248693519093273 ≈ 240.05 feet.
So, the car is approximately 240.05 feet away from the tower.
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