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A cable car rises vertically 1000 feet over a horizontal distance of 5280 feet. What is the angle of elevation of the cable car?*10.72°79.26°

Question

A cable car rises vertically 1000 feet over a horizontal distance of 5280 feet. What is the angle of elevation of the cable car?

  • 10.72°
  • 79.26°
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Solution

To find the angle of elevation of the cable car, we can use the tangent function in trigonometry. The tangent of an angle in a right triangle is defined as the ratio of the opposite side to the adjacent side.

Here, the opposite side is the vertical distance the cable car rises, which is 1000 feet. The adjacent side is the horizontal distance, which is 5280 feet.

So, the tangent of the angle of elevation (let's call it θ) is:

tan(θ) = opposite / adjacent tan(θ) = 1000 / 5280

To find the angle θ, we take the inverse tangent (also known as the arctangent) of the ratio. Most calculators have an arctan or tan^-1 function for this purpose.

θ = arctan(1000 / 5280)

Make sure your calculator is in degree mode, then compute the arctan. The result is the angle of elevation of the cable car.

This problem has been solved

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